FORM 1: IDENTITAS DAN VERIFIKASI
Form
ini bertujuan untuk identifikasi dan verifikasi keabsahan peserta kuliah.
Kerahasiaan isi form ini terjamin, tidak akan diberitahukan ke pihak manapun
tanpa persetujuan dari pengisi form.
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|
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Nama Lengkap
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:
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BUDIONO
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NIM
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:
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B1D014049
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Jenis kelamin
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:
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Laki-laki
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Kelas
|
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5A1
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Tempat, tanggal lahir
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:
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Rarak, 01 Februari 1995
|
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Asal SMA / SMK
|
:
|
SMAN 1 Brang Rea
|
|
Alamat Sementara (kost, rumah sewa,
dll)
|
:
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Jln. Panjitilar Negara No 21 Ampenan
NTB
|
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Alamat Asal (di daerah asal)
|
:
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Sapugara Bree Kec. Brang Rea KSB
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Nomor HP
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:
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+6287863963801
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E-mail
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:
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|
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Nama akun Facebook
|
:
|
budhet aqua
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Jumlah SKS yang telah dicapai
|
:
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84
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IPK
|
:
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3,19
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Nama Ayah
|
:
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Nurdin . M
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Nama Ibu
|
:
|
Mastiawan
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Alamat Orang Tua
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:
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Sapugara Bree Kec. Brang Rea KSB
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Nomor HP Orang Tua
|
:
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+62878636xxxxx
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Pekerjaan Ayah
|
:
|
Tani
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Pekerjaan Ibu
|
:
|
Tani
|
Dengan
ini saya menyatakan bahwa data yang saya isi adalah benar dan saya memang benar
memprogramkan mata kuliah : Ilmu dan Teknologi Telur dan Susu pada Semester Gasal tahun 2016/2017. Saya bersedia menerima sanksi berdasarkan ketentuan yang
berlaku jika saya memberi keterangan
yang tidak benar.
Tugas Mata Kuliah Ilmu dan
Teknologi Telur dan Susu [Kelas 5A1 dan 5A2] Hitunglah Haugh Unit dari Telur dengan 4 (empat) versi rumus jika
diketahui G = 32,2 dan Berat
Telur serta Tinggi Albumen adalah sebagai berikut
|
961
|
B1D014049
|
BUDIONO
|
55,50
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10,00
|
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962
|
|
|
55,50
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9,95
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|
963
|
|
|
55,50
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9,90
|
|
964
|
|
|
55,50
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9,85
|
|
965
|
|
|
55,50
|
9,80
|
|
966
|
|
|
55,50
|
9,75
|
|
967
|
|
|
55,50
|
9,70
|
|
968
|
|
|
55,50
|
9,65
|
|
969
|
|
|
55,50
|
9,60
|
|
970
|
|
|
55,50
|
9,55
|
|
971
|
|
|
55,50
|
9,50
|
|
972
|
|
|
55,50
|
9,45
|
|
973
|
|
|
55,50
|
9,40
|
|
974
|
|
|
55,50
|
9,35
|
|
975
|
|
|
55,50
|
9,30
|
|
976
|
|
|
55,50
|
9,25
|
|
977
|
|
|
55,50
|
9,20
|
|
978
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|
|
55,50
|
9,15
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|
979
|
|
|
55,50
|
9,10
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|
980
|
|
|
55,50
|
9,05
|
961. Dik : W = 55,50 H = 10,00 G
=32,2
a)
Rumus A versi
Prof . Soewarno T Soekarto:
HU = 100
log [
·
Langkah
1
Hitung : W0,37= 55,500,37 = 4,41966 =
(A1)
·
Langkah
2
Hitung : 30 x (A1) =
30 x 4, 41966 = 132,58966 = (A2)
·
Langkah
3
Hitung : (A2) – 100 = 132,58966 – 100 = 32,58966 = (A3)
·
Langkah
4
Hitung : G x (A3) =
32,2 x32.58966 = 1049,38707 = (A4)
·
Langkah
5
Hitung: akar dari
(A4) : √1049,38707 = 32,39424 = (A5)
·
Langkah
6
Hitung : (A5) / 100 =
32,39424/ 100 = 0,32394 = (A6)
·
Langkah 7
Hitung: H – (A6) +
1,9 = 10,00 – 0,32394 + 1,9 = 11,57606 = (A7)
·
Langkah
8
Hitung : Log (A7) = Log 11.57606 = 1,06356 = (A8)
·
Langkah
9
Hitung : 100 x (A8) = 100 x 1,06356 = 106.35607 (Hasil
akhir = nilai HU)
b)
Rumus B
versi Z. Witkowska, et al., 2014:
HU = 100 log (H
·
Langkah
1
Hitung : W0,37= 55,500,37 = 4,41966 =
(A1)
·
Langkah
2
Hitung : 1,7 x (A1) =
1,7 x
4,41966 = 7,51341 = (A2)
·
Langkah 3
Hitung: H – (A2) +
7,70 = 10,00 – 7,51341 + 7,70 = 10,18659 = (A3)
·
Langkah
4
Hitung : Log (A3) = Log 10,18659 = 1,00803 = (A4)
·
Langkah
5
Hitung : 100 x (A4) = 100 x 1,00803 = 100,80287 (Hasil akhir = nilai HU)
c)
Rumus C versi
Vojtěch Kumbár, et al., 2015:
HU = 100 log (H
·
Langkah
1
Hitung : W0,37= 55,500,37 = 4,41966 =
(A1)
·
Langkah
2
Hitung : 1,7 x (A1) =
1,7 x
4,41966 = 7,51341 = (A2)
·
Langkah 3
Hitung: H – (A2) + 7,57
= 10,00 – 7,51341 + 7,57 = 10,05659 = (A3)
·
Langkah
4
Hitung : Log (A3) = Log 10,05659 = 1,00245 = (A4)
·
Langkah
5
Hitung : 100 x (A4) = 100 x 1,00245 = 100,24506 (Hasilakhir=nilaiHU)
d)
Rumus D versi
Stadelman & Cotteril:
HU = 100
log [
·
Langkah
1
Hitung : √G = √32,2 = 5,67450 = (A1)
·
Langkah 2
Hitung : W0,37
= 55,500,37 = 4,41966 = (A2)
·
Langkah
3
Hitung : 30 x (A2) =
30 x 4,41966 = 132,58966 = (A3)
·
Langkah
4
Hitung : (A3) – 100 = 132,58966 – 100
= 32,58966 = (A4)
·
Langkah
5
Hitung : (A1) x (A4)
= 5,67450 x 32,58966 = 184,93017 = (A5)
·
Langkah
6
Hitung : (A5) / 100 =
184,93017 / 100 = 1,84930 = (A6)
·
Langkah 7
Hitung: H – (A6) +
1,9 =
10,00 – 1,84930 + 1,9 = 10,05070 =
(A7)
·
Langkah
8
Hitung : Log (A7) = Log 10,05070 = 1,00220 = (A8)
·
Langkah 9
Hitung : 100 x (A8) = 100 x
1,00220 = 100,21962 (Hasil akhir = nilai HU)
962. Dik
: W = 55,50 H = 9,95 G
=32,2
a)
Rumus A versi
Prof . Soewarno T Soekarto :
HU = 100
log [
= 100 log [
= 100 log [
= 100 log [
= 100 log [
= 100 log [
= 100 log [
= 100 log [
= 100 log 11,52606
= 100 x 1,06168
= 106,16808
b)
Rumus B
versi Z. Witkowska, et al., 2014:
HU = 100 log (H
=
100 log (9,95
=
100 log (9,95
=
100 log (9,95
=
100 log 10,13659
=
100 x 1,00589
=
100,58917
c)
Rumus C versi
Vojtěch Kumbár, et al., 2015:
HU = 100 log (H
= 100 log (9,95
= 100 log (9,95
= 100 log (9,95
= 100 log 10,00659
= 100 x 1,00029
= 100,02859
d)
Rumus D versi
Stadelman & Cotteril:
HU = 100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log 10,00070
=
100 x 1,00003
=
100,00303
963.
Dik
: W = 55,50 H = 9,90 G
=32,2
a)
Rumus A versi
Prof . Soewarno T Soekarto:
HU = 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log 11,47606
= 100 x 1,05979
= 105,97927 Hasil
HU
b)
Rumus B
versi Z. Witkowska, et al., 2014:
HU = 100 log (H
=
100 log (9,90
=
100 log (9,90
=
100 log (9,90
=
100 log 10,08659
=
100 x 1,00374
=
100,37442 Hasil HU
c)
Rumus C versi
Vojtěch Kumbár, et al., 2015:
HU = 100 log (H
= 100 log (9,90
= 100 log (9,90
= 100 log (9,90
= 100 log 9,95659
= 100 x
0,99811
= 99,81104
Hasil HU
d)
Rumus D versi
Stadelman & Cotteril:
HU = 100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log 9,95070
=
100 x 0,99785
=
99,78536 Hasil HU
964. Dik : W = 55,50 H = 9,85 G
=32,2
a)
Rumus A versi
Prof . Soewarno T Soekarto:
HU = 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log 11,42606
= 100 x 1,05790
= 105,78964 Hasil
HU
b)
Rumus B
versi Z. Witkowska, et al., 2014:
HU = 100 log (H
=
100 log (9,85
=
100 log (9,85
=
100 log (9,85
=
100 log 10,03659
=
100 x 1,00159
=
100,15860 Hasil HU
c)
Rumus C versi
Vojtěch Kumbár, et al., 2015:
HU = 100 log (H
= 100 log (9,85
= 100 log (9,85
= 100 log (9,85
= 100 log 9,90659
= 100 x
0,99592
= 99,59240
Hasil HU
d)
Rumus D versi
Stadelman & Cotteril:
HU = 100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log 9,90070
=
100 x 0,99567
=
99,56658 Hasil HU
965. Dik : W = 55,50 H = 9,80 G
=32,2
a)
Rumus A versi
Prof . Soewarno T Soekarto:
HU = 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log [
= 100
log 11,37606
= 100 x 1,05599
= 105,59918 Hasil
HU
b)
Rumus B
versi Z. Witkowska, et al., 2014:
HU = 100 log (H
=
100 log (9,80
=
100 log (9,80
=
100 log (9,80
=
100 log 9,98659
=
100 x 0,99942
=
99,94170 Hasil HU
c)
Rumus C versi
Vojtěch Kumbár, et al., 2015:
HU = 100 log (H
= 100 log (9,80
= 100 log (9,80
= 100 log (9,80
= 100 log 9,85659
= 100 x
0,99373
= 99,37265
Hasil HU
d)
Rumus D versi
Stadelman & Cotteril:
HU = 100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log [
=
100 log 9,85070
=
100 x 0,99347
= 99,34670 Hasil HU
Tabel
1. Rangkuman
Nilai HU dan Selisih Nilai HU Berdasarkan Berbagai Versi Rumus
|
Nomor
Soal
|
Berat
Telur (gram)
|
Tinggi
Albumen (mm)
|
Nilai
HU Berdasarkan Rumus
|
Selisih
Nilai HU
|
||||||||
|
Versi
A
|
Versi
B
|
Versi
C
|
Versi
D
|
A -
B
|
A -
C
|
A -
D
|
B -
C
|
B -
D
|
C –
D
|
|||
|
961
|
55,50
|
10,00
|
106.35607
|
100.80287
|
100.24506
|
100.21962
|
5.55320
|
6.11101
|
6.13645
|
0.55781
|
0.58325
|
0.02544
|
|
962
|
55,50
|
9,95
|
106.16808
|
100.58917
|
100.02859
|
100.00303
|
5.57891
|
6.13949
|
6.16505
|
0.56058
|
0.58614
|
0.02556
|
|
963
|
55,50
|
9,90
|
105.97927
|
100.37442
|
99.81104
|
99.78536
|
5.60485
|
6.16823
|
6.19391
|
0.56338
|
0.58906
|
0.02568
|
|
964
|
55,50
|
9,85
|
105.78964
|
100.15860
|
99.59240
|
99.56658
|
5.63104
|
6.19724
|
6.22306
|
0.56620
|
0.59202
|
0.02582
|
|
965
|
55,50
|
9,80
|
105.59918
|
99.94170
|
99.37265
|
99.34670
|
5.65748
|
6.22653
|
6.25248
|
0.56905
|
0.59500
|
0.02595
|
|
966
|
55,50
|
9,75
|
105.40788
|
99.72372
|
99.15178
|
99.12570
|
5.68416
|
6.25610
|
6.28218
|
0.57194
|
0.59802
|
0.02608
|
|
967
|
55,50
|
9,70
|
105.21573
|
99.50463
|
98.92979
|
98.90357
|
5.71110
|
6.28594
|
6.31216
|
0.57484
|
0.60106
|
0.02622
|
|
968
|
55,50
|
9,65
|
105.02273
|
99.28444
|
98.70665
|
98.68030
|
5.73829
|
6.31608
|
6.34243
|
0.57779
|
0.60414
|
0.02635
|
|
969
|
55,50
|
9,60
|
104.82886
|
99.06312
|
98.48236
|
98.45587
|
5.76574
|
6.34650
|
6.37299
|
0.58076
|
0.60725
|
0.02649
|
|
970
|
55,50
|
9,55
|
104.63413
|
98.84067
|
98.25691
|
98.23028
|
5.79346
|
6.37722
|
6.40385
|
0.58376
|
0.61039
|
0.02663
|
|
971
|
55,50
|
9,50
|
104.43852
|
98.61707
|
98.03028
|
98.00351
|
5.82145
|
6.40824
|
6.43501
|
0.58679
|
0.61356
|
0.02677
|
|
972
|
55,50
|
9,45
|
104.24203
|
98.39232
|
97.80246
|
97.77555
|
5.84971
|
6.43957
|
6.46648
|
0.58986
|
0.61677
|
0.02691
|
|
973
|
55,50
|
9,40
|
104.04464
|
98.16640
|
97.57344
|
97.54639
|
5.87824
|
6.47120
|
6.49825
|
0.59296
|
0.62001
|
0.02705
|
|
974
|
55,50
|
9,35
|
103.84635
|
97.93929
|
97.34320
|
97.31601
|
5.90706
|
6.50315
|
6.53034
|
0.59609
|
0.62328
|
0.02719
|
|
975
|
55,50
|
9,30
|
103.64715
|
97.71099
|
97.11174
|
97.08440
|
5.93616
|
6.53541
|
6.56275
|
0.59925
|
0.62659
|
0.02734
|
|
976
|
55,50
|
9,25
|
103.44703
|
97.48149
|
96.87904
|
96.85156
|
5.96554
|
6.56799
|
6.59547
|
0.60245
|
0.62993
|
0.02748
|
|
977
|
55,50
|
9,20
|
103.24599
|
97.25077
|
96.64508
|
96.61745
|
5.99522
|
6.60091
|
6.62854
|
0.60569
|
0.63332
|
0.02763
|
|
978
|
55,50
|
9,15
|
103.04401
|
97.01881
|
96.40986
|
96.38208
|
6.02520
|
6.63415
|
6.66193
|
0.60895
|
0.63673
|
0.02778
|
|
979
|
55,50
|
9,10
|
102.84109
|
96.78561
|
96.17336
|
96.14542
|
6.05548
|
6.66773
|
6.69567
|
0.61225
|
0.64019
|
0.02794
|
|
980
|
55,50
|
9,05
|
102.63722
|
96.55115
|
95.93556
|
95.90747
|
6.08607
|
6.70166
|
6.72975
|
0.61559
|
0.64368
|
0.02809
|
Tq
ReplyDeleteBang, kita sama sama mahasiswa unram. Boleh minta laporan padang pengembalaan gak?
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